Define the PHI (logarithmic) temperature scale in terms of the ideal gas scale:
Phi = 739.9 x (ln K / ln 10) - 1797.79
| Kelvin | Celsius | Phi |
|---|---|---|
| 0.00 | -273.15 | -infinity |
| 1.00 | -272.15 | -1797.79 |
| 10.00 | -263.15 | -1059.89 |
| 100.00 | -173.15 | -321.99 |
| 273.15 | 0.00 | 0.03 |
| 298.15 | 25.00 | 28.10 |
| 310.15 | 37.00 | 40.74 |
| 373.15 | 100.00 | 100.00 |
| 1000.00 | 726.88 | 415.91 |
| 10000.00 | 9726.85 | 1153.81 |
| 100000.00 | 99726.85 | 1891.71 |
| 1000000.00 | 999726.90 | 2629.61 |
Divides the liquid water range into 100 degrees; makes the cryogenic range within 2000 degrees (negative), the chemical range within 1000 degrees and the nuclear/stellar range within 2500 degrees.
- YHY = E (H=Hamiltonian=D^2, Y=Wavefunction, E= 'total' energy = K + P)
- D(Y^2) = 2 Y D(Y)
- D^2(Y^2) = D(D(Y^2)) = D(2 Y D(Y) ) = 2 Y D^2(Y) + 2 (D(Y))^2
- 0.5 D^2(Y^2) = Y D^2(Y) + (D(Y))^2 = YHY + (D(Y))^2
- (D(Y))^2 = E/V = energy density.
- D(Arc length) = ( 1 + (D(Y))^2)^0.5
- D^2(P) = D (D(P)) where P is a scalar Potential
- D(P) = F! where F! is the vector force due to the gradient in a scalar potential.
- D(F!) = S where S is the source due to the divergence of a vector force.
- mass = m
- momentum = m(v)
- kinetic energy = m(v^2)/2
- then in general: for n=0 to 2 we have m(v^n)/n!
- But v = ds/dt gives the required connection.
- Finally what physical quantity is obtained for n=3 and equals m (v^3)/6?
+/- (1/2) h/2 PI = +/-(1/2)LSB.
